Grind75 Notes
  • README
  • week-1
    • Two Sum
    • Valid Parentheses
    • Merge Two Sorted Lists
    • Best Time to Buy and Sell Stock
    • Valid Palindrome
    • Invert Binary Tree
    • Valid Anagram
    • Binary Search
    • Flood Fill
    • Lowest Common Ancestor of a Binary Search Tree
    • Balanced Binary Tree
    • Linked List Cycle
    • Implement Queue using Stacks
  • week-2
    • First Bad Version
    • Ransom Note
    • Climbing Stairs
    • Longest Palindrome
    • Reverse Linked List
    • Majority Element
    • Add Binary
    • Diameter of Binary Tree
    • Middle of the Linked List
    • Maximum Depth of Binary Tree
    • Contains Duplicate
    • Maximum Subarray
  • week-3
    • Insert Interval
    • 01 Matrix
    • K Closest Points to Origin
    • Longest Substring Without Repeating Characters
    • 3Sum
    • Binary Tree Level Order Traversal
    • Clone Graph
    • Evaluate Reverse Polish Notation
  • week-4
    • Course Schedule
    • Implement Trie (Prefix Tree)
    • Coin Change
    • Product of Array Except Self
    • Min Stack
    • Validate Binary Search Tree
    • Number of Islands
    • Rotting Oranges
  • week-5
    • Search in Rotated Sorted Array
    • Combination Sum
    • Permutations
    • Merge Intervals
    • Lowest Common Ancestor of a Binary Tree
    • Time Based Key-Value Store
    • Accounts Merge
    • Sort Colors
  • week-6
    • Word Break
    • Partition Equal Subset Sum
    • String to Integer (atoi)
    • Spiral Matrix
    • Subsets
    • Binary Tree Right Side View
    • Longest Palindromic Substring
    • Unique Paths
    • Construct Binary Tree from Preorder and Inorder Traversal
  • week-7
    • Container With Most Water
    • Letter Combinations of a Phone Number
    • Word Search
    • Find All Anagrams in a String
    • Minimum Height Trees
    • Task Scheduler
    • LRU Cache
  • week-8
    • Kth Smallest Element in a BST
    • Minimum Window Substring
    • Serialize and Deserialize Binary Tree
    • Trapping Rain Water
    • Find Median from Data Stream
    • Word Ladder
    • Basic Calculator
    • Maximum Profit in Job Scheduling
    • Merge k Sorted Lists
    • Largest Rectangle in Histogram
Powered by GitBook
On this page
  • Problem
  • Pseudocode
  • Solution
  • Time and Space Complexity
  1. week-5

Time Based Key-Value Store

PreviousLowest Common Ancestor of a Binary TreeNextAccounts Merge

Last updated 2 years ago

Problem

Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.

Implement the TimeMap class:

  • TimeMap() Initializes the object of the data structure.

  • void set(String key, String value, int timestamp) Stores the key key with the value value at the given time timestamp.

  • String get(String key, int timestamp) Returns a value such that set was called previously, with timestamp_prev <= timestamp. If there are multiple such values, it returns the value associated with the largest timestamp_prev. If there are no values, it returns "".

Example 1:

Input
["TimeMap", "set", "get", "get", "set", "get", "get"]
[[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]
Output
[null, null, "bar", "bar", null, "bar2", "bar2"]
Explanation
TimeMap timeMap = new TimeMap();
timeMap.set("foo", "bar", 1);  // store the key "foo" and value "bar" along with timestamp = 1.
timeMap.get("foo", 1);         // return "bar"
timeMap.get("foo", 3);         // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".
timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.
timeMap.get("foo", 4);         // return "bar2"
timeMap.get("foo", 5);         // return "bar2"

Pseudocode

- don't understand code, please review

Solution

var TimeMap = function () {
  this.map = new Map();
};

/**
 * @param {string} key
 * @param {string} value
 * @param {number} timestamp
 * @return {void}
 */
TimeMap.prototype.set = function (key, value, timestamp) {
  if (!this.map.has(key)) {
    this.map.set(key, []);
  }

  this.map.get(key).push([timestamp, value]);
};

/**
 * @param {string} key
 * @param {number} timestamp
 * @return {string}
 */
TimeMap.prototype.get = function (key, timestamp) {
  if (!this.map.has(key)) {
    return "";
  }

  if (timestamp < this.map.get(key)[0][0]) {
    return "";
  }

  let left = 0;
  let right = this.map.get(key).length;

  while (left < right) {
    const mid = Math.floor((left + right) / 2);

    if (this.map.get(key)[mid][0] <= timestamp) {
      left = mid + 1;
    } else {
      right = mid;
    }
  }

  if (right > left) {
    return "";
  }

  return this.map.get(key)[right - 1][1];
};

/**
 * Your TimeMap object will be instantiated and called as such:
 * var obj = new TimeMap()
 * obj.set(key,value,timestamp)
 * var param_2 = obj.get(key,timestamp)
 */

Time and Space Complexity

Time

  • What did the code do

  • Total -

Space

  • What did the code do

  • Total -

Loading...LeetCode
Logo