Given the head of a singly linked list, return the middle node of the linked list.
If there are two middle nodes, return the second middle node.
Example 1:
Input: head = [1,2,3,4,5]
Output: [3,4,5]
Explanation: The middle node of the list is node 3.
Example 2:
Input: head = [1,2,3,4,5,6]
Output: [4,5,6]
Explanation: Since the list has two middle nodes with values 3 and 4, we return the second one.
Pseudocode
traverse linked list and store each node in an array, return (length / 2) + 1 from array
fast and slow pointer
https://leetcode.com/problems/middle-of-the-linked-list/solutions/1651600/python-java-c-simple-solution-one-pass-beginner-friendly-detailed-explanation/
Solution
varmiddleNode=function(head) {let stack = []let cur = headwhile(cur) {stack.push(cur) cur =cur.next }let mid =Math.floor(stack.length/2)return stack[mid]}
Time and Space Complexity
Time
Iterate through the linked list to find the length, return the middle node