Given the root of a binary tree, determine if it is a valid binary search tree (BST).
A valid BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
Example 1:
Input: root = [2,1,3]
Output: true
Example 2:
Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.
Pseudocode
- use properties of BST to validate that left and right child are following rules
Solution
varisValidBST=function (root) {functionwalk(root, minVal, maxVal) {// base conditionif (!root) {returntrue; }// preif (root.val <= minVal ||root.val >= maxVal) {returnfalse; }// recurse// left node can't be larger than parent node// right node must be larger than parent nodereturn (walk(root.left, minVal,root.val) &&walk(root.right,root.val, maxVal) );// post }returnwalk(root,-Infinity,Infinity);};