Two Sum

Loading...LeetCode

Problem

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly** one solution**, and you may not use the same element twice.

You can return the answer in any order.

Pseudocode

- loop thorugh the array of integers
- find the complement of the current integer
    - complement = target - nums
    - store complement in a Map as a key, with index with value
        - [k, v] = [complement, i]
- if the current integer is found in the complement
    - return current index and index of complement

Solution

var twoSum = function (nums, target) {
  let map = new Map();
  let result = [];

  for (let i = 0; i < nums.length; i++) {
    let complement = target - nums[i];

    // find complement for nums[i]
    if (map.has(nums[i])) {
      result.push(i, map.get(nums[i]));
      return result;
    } else {
      map.set(complement, i);
    }
  }
};

Time and Space Complexity

Time

• Loops through the array once - O(N)

• Map operations are constant time

• Total - O(N)

Space

• Stores complement of each element in a Map

  • Worst case scenario is that complement is in the last position of the array

• Total - O(N)