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  • Problem
  • Pseudocode
  • Solution
  • Time and Space Complexity
  1. week-1

Linked List Cycle

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Last updated 2 years ago

Problem

Given head, the head of a linked list, determine if the linked list has a cycle in it.

There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next pointer. Internally, pos is used to denote the index of the node that tail's next pointer is connected to. Note that pos is not passed as a parameter.

Return true if there is a cycle in the linked list. Otherwise, return false.

Example 1:

Input: head = [3,2,0,-4], pos = 1
Output: true
Explanation: There is a cycle in the linked list, where the tail connects to the 1st node (0-indexed).

Example 2:

Input: head = [1,2], pos = 0
Output: true
Explanation: There is a cycle in the linked list, where the tail connects to the 0th node.

Example 3:

Input: head = [1], pos = -1
Output: false
Explanation: There is no cycle in the linked list.

Pseudocode

traversing a cylical graph with a single pointer results in an infinite loop as there is not terminating null nodes.

if two pointers are used, with one of the pointer travelling twice as fast as the other, at some point these two pointers will meet.

Solution

var hasCycle = function (head) {
  let fast = head;
  let slow = head;

  while (fast !== null && fast.next !== null) {
    fast = fast.next.next;
    slow = slow.next;

    if (fast === slow) {
      return true;
    }
  }

  return false;
};

Time and Space Complexity

Time

  • A while loop that terminates when there's a null node, or when fast = slow. Complete traversal of the linked list O(N)

  • Total - O(N)

Space

  • Memory requirements are constant as pointer assignments are constant time O(1)

  • Total - O(1)

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