Min Stack

Min Stack - LeetCodeLeetCode

Problem

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

Implement the MinStack class:

• MinStack() initializes the stack object.

• void push(int val) pushes the element val onto the stack.

• void pop() removes the element on the top of the stack.

• int top() gets the top element of the stack.

• int getMin() retrieves the minimum element in the stack.

You must implement a solution with O(1) time complexity for each function.

Example 1:

Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output
[null,null,null,null,-3,null,0,-2]
Explanation
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top();    // return 0
minStack.getMin(); // return -2

Pseudocode

- similar to a min heap, but simplified

Solution

// https://leetcode.com/problems/min-stack/
var MinStack = function () {
  this.data = [];
  this.min = [];
  this.length = 0;
};

/**
 * @param {number} val
 * @return {void}
 */
MinStack.prototype.push = function (val) {
  if (this.length === 0) {
    this.data[0] = val;
    this.min[0] = val;
    this.length++;
  } else {
    this.data[this.length] = val;

    let currMin = this.min[this.length - 1];

    if (currMin > val) {
      this.min[this.length] = val;
    } else {
      this.min[this.length] = currMin;
    }

    this.length++;
  }
};

/**
 * @return {void}
 */
MinStack.prototype.pop = function () {
  // this.min[this.length - 1] = undefined
  // this.data[this.length - 1] = undefined
  this.length--;
};

/**
 * @return {number}
 */
MinStack.prototype.top = function () {
  return this.data[this.length - 1];
};

/**
 * @return {number}
 */
MinStack.prototype.getMin = function () {
  return this.min[this.length - 1];
};

/**
 * Your MinStack object will be instantiated and called as such:
 * var obj = new MinStack()
 * obj.push(val)
 * obj.pop()
 * var param_3 = obj.top()
 * var param_4 = obj.getMin()
 */

Time and Space Complexity

Time

• What did the code do

• Total -

Space

• What did the code do

• Total -